-16x^2=160x-336=0

Solution for -16x^2=160x-336=0 equation:

-16x^2=160x-336=0

We move all terms to the left:

-16x^2-(160x-336)=0

We get rid of parentheses

-16x^2-160x+336=0

a = -16; b = -160; c = +336;
Δ = b2-4ac
Δ = -1602-4·(-16)·336
Δ = 47104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{47104}=\sqrt{1024*46}=\sqrt{1024}*\sqrt{46}=32\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-32\sqrt{46}}{2*-16}=\frac{160-32\sqrt{46}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+32\sqrt{46}}{2*-16}=\frac{160+32\sqrt{46}}{-32}
$